sqlite建表语句(特别是外键问题)
下面图表示两个表关系：
//表1User_invite
create table User_invite(
Invite_id INTEGER PRIMARY KEY, //注意：这里就代表是自动增长
user_id INTEGER,
Invite_date DATE ,
Invite_place VARCHAR(20) NOT NULL,
Invite_kind VARCHAR(20),
Invite_title VARCHAR(20),
Invite_other VARCHAR(50),
Invite_goodCount INTEGER,
Invite_talkCount VARCHAR(20),
Invite_enrollCount VARCHAR(20),
FOREIGN KEY (user_id ) REFERENCES User_info(user_id)); //注意这里：写的外键要写到最后，否则会出现Error: unknown column "user_id" in foreign key definition
故还有要先执行下面的
//必须在运行时打开, 因为 默认是关闭的PRAGMA foreign_keys = ON;
//插入语句
insert into User_invite(user_id,Invite_date,
Invite_place,Invite_kind,
Invite_title,Invite_other,
Invite_goodCount,Invite_talkCount,
Invite_enrollCount)
values('1','2012-12-12','太原','辅导','辅导','无','1','很好','10');
//表2User_infor
create table User_info(
user_id INTEGER PRIMARY KEY,
user_name VARCHAR(50) NOT NULL ,
user_password VARCHAR(20) NOT NULL,
user_credit INTEGER,
user_sex VARCHAR(2),
user_age INTEGER,
User_constellation VARCHAR(50),
User_state INTEGER); //在线为1，离线为0 //用数字表示几颗星，为信用标志
//插入语句
insert into User_info(user_name,user_password,user_credit, user_sex,user_age,User_constellation,User_state) values('xiaoming','123','5','男','22','无','1');
insert into User_info(user_name,user_password,user_credit, user_sex,user_age,User_constellation,User_state) values('张三','123','2','男','20','无','1');
update mytab set name='liming' where birthday='1992-12-12';
update mytab set name='zhangsan' where birthday='1993-10-12';
update mytab set name='wangwu' where birthday='1993-02-12';
update mytab set name='xiaoming' where birthday='1993-11-12';
====进入Android中的数据库在cmd中敲这样的命令（注意这里首先将模拟器打开或有真实的手机）======
# cd data/data/org.lxh.demo/databases
ls
sqlite3 xxx.db 即可
--------------
同时也可以用 命令 “.table” 查看已经建好的表，也可以”.schema“ 查看表的结构
--------------
结果如下：
正文到此结束
热门推荐
相关文章
Loading...
![[HBLOG]公众号](http://www.liuhaihua.cn/img/qrcode_gzh.jpg)
